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22 changes: 17 additions & 5 deletions Sprint-2/improve_with_precomputing/common_prefix/common_prefix.py
Original file line number Diff line number Diff line change
Expand Up @@ -7,12 +7,24 @@ def find_longest_common_prefix(strings: List[str]):

In the event that an empty list, a list containing one string, or a list of strings with no common prefixes is passed, the empty string will be returned.
"""

if len(strings) < 2:
return ""

# Sorting first (O(n log n * k)) means the longest common prefix between
# ANY two strings in the list is guaranteed to be between two ADJACENT
# strings after sorting. This lets us check only n-1 adjacent pairs
# instead of comparing every pair (O(n^2 * k) in the original version),
# reducing the overall complexity to O(n log n * k).

strings = sorted(strings)

longest = ""
for string_index, string in enumerate(strings):
for other_string in strings[string_index+1:]:
common = find_common_prefix(string, other_string)
if len(common) > len(longest):
longest = common

for i in range(len(strings) - 1):
common = find_common_prefix(strings[i], strings[i + 1])
if len(common) > len(longest):
longest = common
return longest


Expand Down
Original file line number Diff line number Diff line change
Expand Up @@ -2,13 +2,15 @@ def count_letters(s: str) -> int:
"""
count_letters returns the number of letters which only occur in upper case in the passed string.
"""
# Precompute a set of all characters in s: O(n) once.
# This turns the `letter.lower() not in s` check (O(n) linear scan,
# making the whole function O(n^2)) into an O(1) set lookup,
# bringing the overall complexity down to O(n).
letters = set(s)
only_upper = set()

for letter in s:
if is_upper_case(letter):
if letter.lower() not in s:
if letter.isupper():
if letter.lower() not in letters:
only_upper.add(letter)
return len(only_upper)


def is_upper_case(letter: str) -> bool:
return letter == letter.upper()
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